Answer:
C3H6 + Br2 = C3H6Br2
The product formed is 1,2-dibromopropane.
The red-brown color of the bromine disappears, leaving a colorless liquid
Step-by-step explanation:
C3H6 + Br2 = C3H6Br2
The product formed is 1,2-dibromopropane.
This is a direct addition reaction. The one molecule of bromine (Br2) joins the organic compound C3H6 to form one molecule of C3H6Br2.
This seemed unlikely at first, but one must look more closely at the C3H6. This is not a straight alkane (e.g., propane). Propane has the formula C3H8:
H3-C-C2-CH3
The molecule C3H6 is propylene (or propene). It has a double bond between two carbons.
H3-CH-CH=CH2
The compound in the question is propylene. When exposed to bromine, the carbon double bond breaks and a bromine atom is attached to each carbon:
H3-CH-CH=CH2 + Br2 = H3-CH-CHBr-CHBr
When propene reacts with bromine, the red-brown color of the bromine is lost and the product is a colorless liquid.