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Patrick, a fellow Precalculus enthusiast, was asked to write down a formula for the function

g obtained by performing the following sequence of transformations on f(x) = 1/x

Patrick, a fellow Precalculus enthusiast, was asked to write down a formula for the-example-1
asked
User Ttom
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1 Answer

1 vote

I can help you with your math question.

The sequence of transformations on f(x) = 1/x is:

- Reflect f(x) across the x-axis

- Shift f(x) left 2 units

- Stretch f(x) vertically by a factor of 3

- Shift f(x) up 5 units

To write down a formula for g(x), we need to apply these transformations in the reverse order. That is:

- Start with f(x) = 1/x

- Shift it down 5 units: f(x) - 5 = 1/x - 5

- Compress it vertically by a factor of 3: (f(x) - 5)/3 = (1/x - 5)/3

- Shift it right 2 units: (f(x) - 5)/3 + 2 = (1/x - 5)/3 + 2

- Reflect it across the x-axis: -(f(x) - 5)/3 + 2 = -(1/x - 5)/3 + 2

Therefore, the formula for g(x) is:

g(x) = -(1/x - 5)/3 + 2

Patrick's answer of g(x) = 2x + 5 is incorrect because he did not apply the transformations correctly. He made the following mistakes:

- He multiplied f(x) by 2 instead of dividing it by 3, which changed the shape of the graph from a hyperbola to a line.

- He added 5 to x instead of subtracting it, which shifted the graph in the wrong direction.

- He did not reflect the graph across the x-axis, which changed the sign of the function.

I hope this helps you understand how to write down a formula for a transformed function. If you have any more questions, feel free to ask me.

Explanation:

answered
User Sam Axe
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7.8k points
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