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Q3.
Please help me as soon as possible.

Q3. Please help me as soon as possible.-example-1
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User Loyal
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1 Answer

4 votes

Answer:

42 units

Explanation:

Given:

ABCD is a parallelogram.

ABE is a equilateral triangle.


\sf \overline{BE}=\overline{DE}=7

To find:

Perimeter of parallelogram.

Solution:

Since all sides of equilateral triangle are equal. so,


\sf \overline{AB}=\overline{AE}=7

And

Oopposite side of the parallelogram are also equal,

So,


\sf \overline{AB}=\overline{CD}=7


\sf \overline{BC}=\overline{AD}=\overline{AE}+\overline{ED}=7+7=14

Now,

The perimeter of the parallelogram is equal to the sum of all sides:


\begin{aligned} \textsf{The perimeter of the parallelogram} &\sf = \overline{AB}+\overline{BC}+\overline{CD}+\overline{AD} \\\\ &\sf = \textsf{Substitute the value:}\\\\ &\sf = 7+14+7+14\\\\ &\sf = 42 units \end{aligned}

Therefore, the perimeter of a parallelogram is 42 units.

answered
User Tmgirvin
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8.8k points

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