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A student dissolves 8.1 g of styrene (C8H8) in 250. mL of a solvent with a density of 0.90 g/mL. The student notices that the volume of the solvent does not change when the styrene dissolves in it.

Calculate the molarity and molality of the student's solution.

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User SharpLu
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8.1k points

1 Answer

4 votes

Step-by-step explanation:

To calculate the molarity and molality of the student's solution, we'll follow these steps:

Step 1: Calculate the moles of styrene (C8H8).

Step 2: Calculate the volume of the solvent in liters.

Step 3: Calculate the molarity (M).

Step 4: Calculate the molality (m).

Step 1: Calculate the moles of styrene (C8H8):

Molar mass of styrene (C8H8):

Carbon (C) has a molar mass of approximately 12.01 g/mol.

Hydrogen (H) has a molar mass of approximately 1.01 g/mol.

Molar mass of C8H8 = (8 × 12.01 g/mol) + (8 × 1.01 g/mol) = 96.08 g/mol

Now, calculate moles:

Moles of styrene = Mass (g) / Molar mass (g/mol)

Moles of styrene = 8.1 g / 96.08 g/mol ≈ 0.0843 mol

Step 2: Calculate the volume of the solvent in liters:

Given density of the solvent = 0.90 g/mL

Volume of the solvent = 250 mL = 0.25 L (since 1 mL = 0.001 L)

Step 3: Calculate the molarity (M):

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity (M) = 0.0843 mol / 0.25 L ≈ 0.337 M

Step 4: Calculate the molality (m):

Molality (m) = Moles of solute / Mass of solvent (in kg)

Mass of solvent = Volume of solvent (in L) × Density of solvent (in g/mL) / 1000 (to convert g to kg)

Mass of solvent = 0.25 L × 0.90 g/mL / 1000 = 0.225 kg

Molality (m) = 0.0843 mol / 0.225 kg ≈ 0.374 mol/kg

So, the molarity of the solution is approximately 0.337 M, and the molality of the solution is approximately 0.374 mol/kg.

answered
User Michael Jasper
by
8.7k points
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