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What is the mass of the air in a room measuring 8 meters in length, 5 meters in width, and 4 meters in height, given that the density of air is 1.3 kg/m^3?

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The mass of the air in a room measuring 8m by 5m by 4m, given that the density of the air is 1.3 kg/m^3, is 208 kg.

To calculate the mass of the air in a room, you need to find the volume of the room first and then multiply it by the density of the air. The volume of a room is calculated by multiplying its length, width, and height. In this scenario, the room is 8 meters long, 5 meters wide, and 4 meters high. Therefore, the volume of the room is 8m * 5m * 4m = 160 cubic meters. The density of the air is given as 1.3 kg/m^3.

To find the mass, multiply the volume by the density, 1.3 kg/m^3 * 160 m^3 = 208 kg. Hence, the mass of the air in the room is 208 kg.

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