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Solve by Addition/Elimination "4x + 2y = 2 ,3x - y = -1 (put both into graph, find where they both cross the point)"

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Answer:

Explanation:

To solve the system of linear equations using the addition/elimination method, you can manipulate the equations to eliminate one of the variables. Here's how you can do it:

Start with the original equations:

4x + 2y = 2 ...(1)

3x - y = -1 ...(2)

To eliminate "y," multiply equation (2) by 2 so that the coefficients of "y" in both equations become equal:

2(3x - y) = 2(-1)

This simplifies to:

6x - 2y = -2 ...(3)

Now, you have the modified equation (3) and the original equation (1). You can add these two equations together to eliminate "y":

(4x + 2y) + (6x - 2y) = 2 + (-2)

Combine like terms:

4x + 6x = 0

10x = 0

Divide by 10 to solve for "x":

x = 0

Now that you have the value of "x," you can substitute it into equation (2) to solve for "y":

3x - y = -1

3(0) - y = -1

0 - y = -1

-y = -1

To isolate "y," multiply both sides by -1:

y = 1

So, the solution to the system of equations is:

x = 0

y = 1

Now, you can graphically represent this solution by plotting the point (0, 1) on a coordinate plane. This is the point where the two lines representing the equations intersect.

Here's how the equations look when graphed:

Equation (1): 4x + 2y = 2

Equation (2): 3x - y = -1

The point of intersection is (0, 1).

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User Rdtsc
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