Answer:
Explanation:
I see that you want to find the equation of a linear function that forms a right triangle with the x-axis, y-axis, and has an area of 50 square units. To clarify, let's work through this step by step.
A right triangle can be formed with the x-axis and y-axis as two sides, and the third side represented by the graph of a linear function. The area of this right triangle can be found using the formula for the area of a triangle:
Area = (1/2) * base * height
In this case, one of the legs (base) of the right triangle is along the x-axis, and its length is determined by the x-coordinate at which the linear function crosses the x-axis. The other leg (height) is along the y-axis, and its length is determined by the y-coordinate at which the linear function crosses the y-axis.
Let's assume that the linear function is of the form:
f(x) = mx + b
where "m" is the slope and "b" is the y-intercept.
The x-coordinate where the linear function crosses the x-axis is given by:
x-coordinate = -b/m
The y-coordinate where the linear function crosses the y-axis is "b."
Now, let's calculate the area of the right triangle:
Area = (1/2) * (length of base) * (length of height)
Area = (1/2) * (-b/m) * b
Given that the area is 50 square units, we can set up the equation:
(1/2) * (-b/m) * b = 50
Now, you can solve this equation for "m" and "b" to find the equation of the linear function that satisfies the given conditions.