Question

A quarter rolls off a table with an initial horizontal velocity of 0.24 m/s. If the quarter lands 0.42 seconds later on the ground, how high is the table?

Answer 1

0.86 m

Step-by-step explanation:

Given in the y direction:

u = 0 m/s

t = 0.42 s

a = 9.8 m/s²

Find: s

s = u t + ½ a t²

s = (0 m/s) (0.42 s) + ½ (9.8 m/s²) (0.42 s)²

s = 0.86 m