Question

0.378 g H₂O, 25.00 mL sample of a 0.100 M solution of HCl reacts with excess NaOH. What mass of H₂O is produced in the reaction? HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

Answer 1

To find the mass of H2O produced, calculate the number of moles of HCl and use the balanced chemical equation.

Step-by-step explanation:

To find the mass of H2O produced, we need to determine the limiting reactant in the reaction. First, calculate the number of moles of HCl using the formula: moles = Molarity x Volume (in L). Then, compare the number of moles of HCl with NaOH to determine the limiting reactant. In this case, NaOH is in excess, so HCl is the limiting reactant. Use the balanced chemical equation to find the moles of H2O produced, and then convert moles to grams using the molar mass of H2O.

Using the given information:

Moles of HCl = 0.100 mol/L x 0.025 L = 0.0025 mol HCl

Moles of H2O = Moles of HCl (from balanced equation)

= 0.0025 mol HCl x (1 mol H2O / 2 mol HCl)

= 0.00125 mol H2O

Mass of H2O = Moles of H2O x Molar mass of H2O

= 0.00125 mol H2O x 18.02 g/mol

= 0.022 g

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