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(3x^-4y^4)/(8z^-2x^3)

(3x^-4y^4)/(8z^-2x^3)
asked 39.8k views
2 votes
(3x^-4y^4)/(8z^-2x^3)

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User UltraMaster
by
8.1k points

2 Answers

0 votes

Answer:

Explanation:

Step1 3x^-4Y^4

8Z^-2X^3

Step2 3Y^4

8Z^-2x^7

Solution 3Y^4Z^2

8x^7

answered
User Gul Ershad
by
7.8k points
4 votes

3y^4 Z^2/8x^7

Step-by-step explanation: Cancel terms that are in both the numerator and denominator

answered
User Thomee
by
8.5k points
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