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A 10 inch beam is in the path of a conduit run from a junction box, which is located 38 inches from the beam. the beam is to be bypassed by a 30 degree offset, with the second offset bend occurring at the corner of the beam. at what distances from the outlet box will the bends be marked on a length of 1 inch emt? a. 8 inches and 48 inches b. 18 inches and 38 inches c. 38 inches and 40 1/2 inches d. 20 1/2 inches and 40 1/2 inches

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User Bdar
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Answer: The answer is d. 20 1/2 inches and 40 1/2 inches.

Explanation: The first offset bend will be 20 1/2 inches from the outlet box, followed by a straight run of 10 inches, and then the second offset bend will be 40 1/2 inches from the outlet box.

Here is the explanation:

The first offset bend is a 30 degree bend, so the distance from the outlet box to the center of the bend is 38 / (tan 30) = 20 1/2 inches.

The straight run of 10 inches is the distance from the center of the first offset bend to the corner of the beam.

The second offset bend is also a 30 degree bend, so the distance from the corner of the beam to the center of the bend is 10 / (tan 30) = 40 1/2 inches.

Therefore, the distances from the outlet box to the two bends are 20 1/2 inches and 40 1/2 inches.

So the answer is (d).

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User FJDU
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