Question

Pipe A can fill a tank in 3 hours. Pipe B can fill itin 4 hours. An outlet pipe C can empty the fulltank in 6 hours. If all three pipes are kept opensimultaneously, in how many hours will the tankbe half full?

Answer 1

The tank will be half full in about 1.03 hours when all three pipes - Pipe A, Pipe B and Pipe C, are kept open simultaneously.

Step-by-step explanation:

The subject of this question is Mathematics, specifically, it's about rate problems. In this problem, there are three pipes - Pipe A, Pipe B and Pipe C, each with a different rate. Pipe A fills the tank in 3 hours, Pipe B fills it in 4 hours, and Pipe C can empty it in 6 hours. When all pipes operate simultaneously, we need to calculate when the tank will be half full.

First, we calculate the individual rates of pipes- Pipe A's rate is 1/3 tank/hour, Pipe B's is 1/4 tank/hour, and Pipe C empties the tank at a rate of 1/6 tank/hour. The combined rate is the sum of the filling rates minus the emptying rate, which is (1/3 + 1/4 - 1/6) = 7/12 tank/hour.

To find out when the tank is half full, we need to divide 0.5 (representing half the tank) by 7/12 (the combined rate). This gives us the answer, about 1.03 hours.

Learn more about Rate Problems