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5 votes
what amount of time is required for the concentration of a to decrease from 0.800 m to 0.120 m in the zero-order reaction a → b? (k = 0.0567 m*s⁻¹)

asked
User Jeff Hay
by
7.6k points

2 Answers

6 votes

Final answer:

To calculate the time required for the concentration of A to decrease from 0.800 M to 0.120 M in a zero-order reaction with k = 0.0567 M·s⁻¹, use the formula Δt = ([A]1 - [A]2) / k, resulting in approximately 12.0 seconds.

Step-by-step explanation:

The question is asking to calculate the time required for the concentration of a substance A to decrease from 0.800 M to 0.120 M in a zero-order reaction, given that the rate constant (k) is 0.0567 M·s⁻¹. The formula for the time (Δt) taken in a zero-order reaction where the concentration decreases from [A]1 to [A]2 is given by Δt = ([A]1 - [A]2) / k. Substituting the given values:

  • Δt = (0.800 M - 0.120 M) / 0.0567 M·s⁻¹
  • Δt = (0.680 M) / 0.0567 M·s⁻¹
  • Δt = 11.9885 s

Therefore, it would take approximately 12.0 seconds for the concentration of A to decrease from 0.800 M to 0.120 M under zero-order kinetics.

answered
User Svenhalvorson
by
8.0k points
2 votes

Final answer:

To calculate the time for the concentration of A to decrease from 0.800 M to 0.120 M in a zero-order reaction with a rate constant k of 0.0567 M*s-1, we use the formula t = ∆[A] / k. The resulting time is approximately 12.0 seconds.

Step-by-step explanation:

The time required for the concentration of A to decrease from 0.800 M to 0.120 M in a zero-order reaction can be determined using the rate constant (k) provided. For a zero-order reaction, the rate of reaction is given by the equation:

rate = k[A]0

Since the reaction is zero-order, the rate is constant, and [A]0 is equal to 1, making the rate equal to k. The change in concentration over time can be expressed as:

∆[A] = -kt

Thus, the time (t) required for the concentration to change can be calculated by rearranging the equation:

t = ∆[A] / k

Substituting the given values, the initial concentration (0.800 M), the final concentration (0.120 M), and the rate constant (0.0567 M·s⁻¹), we get:

t = (0.800 M - 0.120 M) / 0.0567 M·s⁻¹

t = 0.680 M / 0.0567 M·s⁻¹

t = 11.98909465 s, which can be rounded to 12.0 seconds.

answered
User Lionscribe
by
8.3k points
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