Final answer:
To calculate the time for the concentration of A to decrease from 0.800 M to 0.120 M in a zero-order reaction with a rate constant k of 0.0567 M*s-1, we use the formula t = ∆[A] / k. The resulting time is approximately 12.0 seconds.
Step-by-step explanation:
The time required for the concentration of A to decrease from 0.800 M to 0.120 M in a zero-order reaction can be determined using the rate constant (k) provided. For a zero-order reaction, the rate of reaction is given by the equation:
rate = k[A]0
Since the reaction is zero-order, the rate is constant, and [A]0 is equal to 1, making the rate equal to k. The change in concentration over time can be expressed as:
∆[A] = -kt
Thus, the time (t) required for the concentration to change can be calculated by rearranging the equation:
t = ∆[A] / k
Substituting the given values, the initial concentration (0.800 M), the final concentration (0.120 M), and the rate constant (0.0567 M·s⁻¹), we get:
t = (0.800 M - 0.120 M) / 0.0567 M·s⁻¹
t = 0.680 M / 0.0567 M·s⁻¹
t = 11.98909465 s, which can be rounded to 12.0 seconds.