Question

Solve the following equation
6^2m × 4^-m÷ (3^m)^2​

Answer 1

Explanation:

6^2m × 4^-m÷ (3^m)^2 =
`(6^(2m) * 4^(-m))/((3^(m))^(2))\\`

`= ((3*2)^(2m)*(2^(2))^(-m))/(3^(2*m))\\\\=(3^(2m)*2^(2m)*2^(-2m))/(3^(2m))\\\\\\=3^(2m-2m)*2^(2m-2m)\\\\=3^(0)*2^(0)\\\\=1*1\\= 1`

Hint:

`a^(m)*a^(n)= a^(m+n)\\\\(a^(m))^(n)=a^(m*n)\\\\(a^(m))/(a^(n))=a^(m-n)`