Question

Two different schools, school A and school B, attended a conference.

12% of the attendees were teachers, the rest were students.
47% of the attendees were from school A.
48% of the attendees were students from school B.
One of the attendees is selected at random.
Find the probability that they are a teacher from school A.

Answer 1

Let's break down the information provided to find the probability that the randomly selected attendee is a teacher from school A.

1. The total percentage of attendees who were teachers is 12%.

2. The percentage of attendees from school A is 47%.

To find the probability that the selected attendee is a teacher from school A, you need to consider the intersection of these two events (being a teacher and being from school A).

Probability(Teacher from School A) = Probability(Teacher) * Probability(School A)

Probability(Teacher) = 12% = 0.12 (as a decimal)
Probability(School A) = 47% = 0.47 (as a decimal)

Now, calculate the probability of both events happening together:

Probability(Teacher from School A) = 0.12 * 0.47 = 0.0564

So, the probability that the randomly selected attendee is a teacher from school A is 0.0564 or 5.64%.