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2 votes
Consider the following. 5x+4x^(2)

1 Answer

3 votes
5x+4x^2

if we factor the expression:


“take the common factor out of brackets

x*(5+4x)


if you find the roots of a polynomial:


5x+4x^2

f(x)= 5x+4x^2
f(x)=0

5x+4x^2=0

let's find the roots using the discriminant formula

a=5, b=4, c=0

D=b^2-4ac => 16-4*5*0 = 16, D>0

x1,2= -b±√D/2a => -4±4/10 = 0; -4/5 (or -1,25)


-4/5 (-1,25);0

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