Question

X2 + 8x + 16 = 0. solve quadratic equation

Answer 1

To solve the quadratic equation x^2 + 8x + 16 = 0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the following formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = 8, and c = 16. Plugging these values into the quadratic formula, we get:

x = (-8 ± √(8^2 - 4*1*16)) / (2*1)

Simplifying further:

x = (-8 ± √(64 - 64)) / 2

x = (-8 ± √0) / 2

Since the discriminant (√(b^2 - 4ac)) is zero, we have a single real root:

x = -8 / 2

x = -4

Therefore, the solution to the quadratic equation x^2 + 8x + 16 = 0 is x = -4.

Answer 2

Answer: X=-4

Step-by-step explanation:

Using equation x= -b+/-root b^2-4ac the whole divided by 2a.

the equation is ax+bx+c=0,where a not equal to zero.

Here values are a=1, b=8,c=16. So,

lets solve b^2-4ac first. It will be 8^2-(4*1*16)=64-64=0. Root 0=0.

therefore, x=-8+/- 0/2

x = -8/2= -4

x=-4