Question

The outlined content above was added from outside of Formative. Write the slope-intercept form of an equation that passes through the point (-2,3), and is parallel to y=-x+5 y=-x+5

Answer 1

To write the slope-intercept form of an equation that passes through the point (-2,3) and is parallel to y=-x+5, we need to find the slope of the given equation and then use the point-slope form of the linear equation.

Step-by-step explanation:

To write the slope-intercept form of an equation that passes through the point (-2,3) and is parallel to y=-x+5, we need to find the slope of the given equation and then use the point-slope form of the linear equation. The slope-intercept form of an equation is given as y = mx + b, where m is the slope and b is the y-intercept.

1. Step 1: Find the slope of y=-x+5. The given equation is in the form y=mx+b, where m is the slope. In this case, the slope is -1.
2. Step 2: Use the point-slope form of a linear equation. Plug in the values for the slope (m), x-coordinate of the given point (-2), and y-coordinate of the given point (3). The equation will be y - 3 = -1(x - (-2)). Simplifying further, we get y - 3 = -1(x + 2).
3. Step 3: Convert the equation to the slope-intercept form. Distribute the -1 to get y - 3 = -x - 2. Add 3 to both sides to isolate y, resulting in y = -x + 1. Therefore, the slope-intercept form of the equation that passes through the point (-2,3) and is parallel to y=-x+5 is y = -x + 1.

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