Question

Solve: ∫e^u/(1−eu)^2​du

Answer 1

Hi,

Explanation:

`Let's\ say\ v=1-e^u \\\\\displaystyle \int\limits {\frac{e^u } { (1-e^u)^2 }} \, du \\\\\\=\int\limits {(1)/(v^2) } \, dv \ \\\\=-(1)/(u) +C\\\\=-\frac{1 } { 1-e^u } + C`