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The electric field at a point 2 m away from a point charge Q is 18 N/C outwards. The charge Q is:

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Final answer:

The charge Q is found by substituting the given values into Coulomb's law equation and simplifying. Q is equal to the product of the electric field strength (18 N/C) and the square of the distance (2m)², divided by Coulomb's constant (8.99 x 10⁹ Nm²/C²). This yields the charge Q.

Step-by-step explanation:

The magnitude of the electric field E created by a point charge Q at a distance r is given by Coulomb's law, which can be mathematically represented as E = kQ / r², where k is Coulomb's constant equal to 8.99 x 10⁹ Nm²/C². Here you have E = 18 N/C and r = 2 m. We will solve this equation to find Q, the charge that is producing the electric field.

Step 1: Plug known values into the equation: 18 N/C = kQ / (2 m)²

Step 2: Multiply both sides of the equation by r² = (2 m)² to get: Q = E * r² / k

Step 3: Substitute the values to determine Q: Q = 18 N/C * (2 m)² / 8.99 x 10⁹ Nm²/C²

After simplifying, you will find the charge Q.

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