Question

Methane reacts with oxygen to form carbon dioxide and hydrogen gas, according to the balanced chemical reaction shown below. If you have how many gas can be generated if the reaction is performed at STP in the presence of excess methane? CH₄​( g)+O₂​( g)→CO₂​( g)+H₂​( g)

Answer 1

In the given chemical reaction, methane reacts with oxygen to produce carbon dioxide and hydrogen gas. One mole of methane produces one mole of carbon dioxide and one mole of hydrogen gas. At STP, one mole of any gas occupies 22.414 liters.

Step-by-step explanation:

In the given balanced chemical reaction, CH4(g) + O2(g) → CO2(g) + H2(g), methane reacts with oxygen to produce carbon dioxide and hydrogen gas.

To determine the number of moles of gas produced, we need to know the number of moles of methane present.

Assuming we have one mole of methane, it will produce one mole of carbon dioxide and one mole of hydrogen gas.

At STP (standard temperature and pressure), one mole of any gas occupies 22.414 liters.

Therefore, one mole of methane produces 22.414 liters of carbon dioxide and 22.414 liters of hydrogen gas.