Answer: Na₂O
Step-by-step explanation:
Sodium is in group 1, and elements in group 1 always have a charge of 1+, or +:
Na⁺
Oxide is the ion of oxygen, and oxygen is in group 16, and elements in group 16 always have a charge of 2-:
O²⁻
We have our charges of 1+ and 2-, so we balance the charges so that the final formula is balanced; the sum of the charges should be 0, so we need to have a subscript of 2 on Na (2 * +1 = +2):
Na₂⁺
Now, we always put the cation (+ ion) on the left and the anion (- ion) on the right:
Na₂⁺O²⁻
In the final formula, we don't need to include the charges/superscripts, but we need to include the subscripts, which indicate the number of atoms of that element (so, in a molecule of sodium oxide, there are 2 atoms of Na and 1 atom of oxygen).
Our final formula is Na₂O.
I hope this helps! :)