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(a+b+c)^3-a^3-b^3-c^3 = 3(a+b)(b+c)(c+a)

(a+b+c)^3-a^3-b^3-c^3 = 3(a+b)(b+c)(c+a)
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(a+b+c)^3-a^3-b^3-c^3 = 3(a+b)(b+c)(c+a)

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User WTPK
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1 Answer

1 vote

Answer:

Explanation:

answered
User Jesus Monzon Legido
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