Question

An urn contains 2 red balls, 5 blue balls, and 3 white balls. A ball is selected and its color is noted. Then it is replaced. A second ball is selected and its color is noted. Find the probability of selecting 1 white ball then a red ball.

Answer 1

5/10 or 50% percent chance

Explanation:

There are 10 balls total. Since the first one would be replaced all balls are still present the second time. The chance of getting a white ball the first time would be 3/10 since there are 3 white balls. Then it would be put back and the chance to get a red the second time would be 2/10. You add the two together and get 5/10 or 50%.