Question

a school has a rectangular music hall which is (y+15) units long and (y-3) units wide. it also has a rectanglular table tennis hall whose lengtha and breadth are each 3 units longer than that of the music hall. Find their difference in their areas

Answer 1

The difference in the area of a music hall and a table tennis hall, given the dimensions of the music hall as (y+15) by (y-3) and the table tennis hall's dimensions are 3 units more than the music hall's, is 120 square units.

Step-by-step explanation:

The area of a rectangle is calculated by multiplying its length by its width. So, the area of the music hall can be calculated as follows: (y + 15) * (y - 3). The table tennis hall's dimensions are each 3 units more than the music hall's. So, its area would be (y + 15 + 3) * (y - 3 + 3). The difference in the two areas can be calculated by subtracting the smaller area from the larger one, which means [(y + 18) * (y) - (y + 15) * (y - 3)]. Simplifying this expression gives 120.

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