Question

Considet the following case of exponential growth. Complete parts a through c below: The population of a lown with an initial population of 70,000 grows at a rate of 2.5% per year. a. Create an exponential function of the form Q=Q₀​×(1+r)¹. (where r>0 for growth and r<0 for decay) to model the situation described. a=70,000× (Type integers or decimals.) b. Create a table showing the value of the quantity Q for the frst 10 years of growth. (Round to the nearest whole number as needed)

Answer 1

The exponential growth function is Q = 70,000 × (1 + 0.025)¹, representing the growth of the town's population. A table can be created using the function for each of the first 10 years of growth.

Step-by-step explanation:

Given the question, we'll create an exponential growth function. In this case, we have an initial population i.e Q₀ of 70,000 and a rate of growth, r, of 2.5% or 0.025. So, the formula for the exponential growth becomes: Q = 70,000 × (1 + 0.025)¹.

Next, we will create a table for the first 10 years of growth. For example, the population after the first year is Q = 70,000 × (1+0.025)¹ = 71750 (rounded to the nearest whole number), for second year, Q = 70,000 × (1+0.025)² = 73609 and so forth until the 10th year.

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