Part (a)
Focus on triangle ABC.
This triangle is isosceles because AB = CB.
The base angles opposite the congruent sides are congruent angles.
Angle A = angle C = 68 degrees
Let's use that to find angle B of triangle ABC.
A+B+C = 180
68+B+68 = 180
B+136 = 180
B = 180-136
B = 44
Angle ABC is 44 degrees
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Part (b)
angle ABC + angle CBD = angle ABD
angle CBD = angle ABD - angle ABC
angle CBD = 90 - 44
angle CBD = 46 degrees
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Part (c)
Triangle BCD is isosceles because BC = BD.
Let x be the measure of each congruent base angle C and D.
B+C+D = 180
46+x+x = 180
46+2x = 180
2x = 180-46
2x = 134
x = 134/2
x = 67
Angle D is 67 degrees