Answer:
To find the solution of the system of equations, you can use the method of substitution or elimination. I'll use the elimination method here.
Here are the equations:
1. -5a - 5y = -30
2. 10x + 3y = -3
First, let's multiply both sides of the second equation (2) by 5 to make the coefficients of y in both equations cancel when summed:
1. -5a - 5y = -30
2. 50x + 15y = -15
Now, we can add equation (1) and equation (2) to eliminate y:
(-5a - 5y) + (50x + 15y) = (-30) + (-15)
Simplify:
-5a + 50x + 10y = -45
Now, let's solve this equation for y:
10y = -45 - 5a + 50x
10y = -5a + 50x - 45
y = (-5a + 50x - 45) / 10
y = -0.5a + 5x - 4.5
So, the solution to the system of equations is:
x = 5x - 4.5
y = -0.5a + 5x - 4.5