Question

I’ve been stuck on this because I genuinely don’t understand how to do it please help

Answer 1

`\sf\\\angle AOC+\angle COD+\angle DOE=180^o\ \ \ [\textsf{Sum of angles in straight line is 180}^o.]\\\textsf{or, }101^o+44^o+(x-18)^o=180^o\\\textsf{or, }x^o+127^o=180^o\\\textsf{or, }x^o=53^o`

`\sf\\\angle BOE=\angle BOC+\angle COD+\angle DOE\\\textsf{or, }\angle BOE=70^o+44^o+(x-18)^o\\\textsf{or, }\angle BOE=114^o+(53-18)^o=149^o`