Question

Darren wins a coupon for four dollars off lunch specials for each of five days. He pays $75 for his five lunch specials.

Answer 1

Step-by-step explanation:

Per 5 days: Because he has 5 days, we can do $4×5 days which gets us $20 savings in total. Then we subtract the $20 savings from $75 and that gets us to $55 for 5 days in total.

Per day: If we want to calculate per day, we do $55÷5 days = $11 per day.

Answer 2

Let's assume that the cost of each lunch special without the coupon is x dollars.
With the coupon, the cost of each lunch special is (x - 4) dollars.
Darren paid $75 for five lunch specials, so we can write the equation:
5(x - 4) = 75
Expanding the equation, we get:
5x - 20 = 75
Adding 20 to both sides of the equation, we get:
5x = 95
Dividing both sides of the equation by 5, we get:
x = 19
Therefore, the cost of each lunch special without the coupon is $19.
And the cost of each lunch special with the coupon is $19 - $4 = $<<19-4=15>>15.
So, Darren wins a coupon for $4 off each lunch special, and the original cost of each lunch special is $19.