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When you reverse the digits in a certain two digit number you decrease is value by 63.what is the number if the sum of digits is 7

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x, y are the 2 digits.

x + y = 7

what is the value of the 2-digit numbers ?

well, the value of a number is given by the power of 10 of each position multiplied by the digit in that position.

e.g. the value of 456 is actually

456 = 4×10² + 5×10¹ + 6×10⁰

the value of the first number is therefore

x×10¹ + y×10⁰ = 10x + y

the cake if the second number (with reversed digits) is then

y×10¹ + x = 10y + x

and we know that the second number is smaller by 63 than the first number.

so,

10y + x + 63 = 10x + y

it if the first equation x + y = 7 we get e.g.

x = 7 - y

and use that in the main equation :

10y + (7 - y) + 63 = 10(7 - y) + y

10y + 7 - y + 63 = 70 - 10y + y

9y + 70 = 70 - 9y

18y = 0

y = 0

x = 7 - y = 7 - 0 = 7

so, the original number is 70.

the reversed number is 07 or simply 7.

answered
User Jaylyn
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