Question

Find the 12th term of the GP 2,6,18​

Answer 1

`\sf\\\textsf{Solution:}\\\textsf{Given:}\\\textsf{First term(a)} = 2\\\textsf{Common ratio(r) = }(Second\ term(t_2))/(First\ term(t_1))=(6)/(2)=3\\\textsf{Now,}\\\textsf{nth term}(t_n)=ar^(n-1)=2(3)^(n-1)\\\\\therefore\ \textsf{12th term}(t_(12))=2(3)^(12-1)=3(2)^(11)=354294`