Question

What is the unit distance, rounded to the nearest tenth, between the points (-2, 4) and (6, -2)?

Answer 1

formule :

`√(x2-x1)^2 + (y2-y1)^2) =\\\\√((6-(-2))^2+(-2-4)^2) =\\\\√(8^2+6^2) = √(100) \\\\`

→√100 = 10

→The distance between the points (-2, 4) and (6, -2) is therefore 10, rounded to the nearest tenth.