Question

A 9 cm tall object was placed 27 cm in front of a concave mirror of focal length 18 cm. The image distance and the size of the image respectively (with correct sign convention) will be:​

Answer 1

The image distance is 54 cm and the size of the image is 2 times the size of the object.

Step-by-step explanation:

The image distance can be determined using the mirror equation: 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance. Plugging in the given values, we get: 1/18 = 1/v - 1/27. Solving this equation, we find that the image distance (v) is 54 cm.

The size of the image can be determined using the magnification equation: m = -v/u, where m is the magnification, v is the image distance, and u is the object distance. Plugging in the given values, we get: m = -54/27 = -2. Since the magnification is negative, the image is inverted compared to the object. Therefore, the size of the image is 2 times the size of the object.

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