Find the magnitude of these sum of vectors 63.5 101 57

Question

asked Oct 27, 2024 195k views

2 Answers

Zachary Ozer · Answer 1 · 2024-10-28T17:59:20+0000

The magnitude of the sum of the vectors 63.5, 101, and 57 is approximately 132.22.

To find the magnitude of a vector, we need to calculate its Euclidean norm. In this case, the vector is simply the sum of the three given numbers:

vector = [63.5, 101, 57]

Calculating the Euclidean norm:

magnitude = ||vector|| = sqrt(63.5^2 + 101^2 + 57^2) ≈ 132.22

Therefore, the magnitude of the sum of the vectors is approximately 132.22.

Pierre Vieira · Answer 2 · 2024-10-31T03:30:19+0000

The magnitude of the sum of the vectors is 132

The magnitude of the sum of vectors by finding the square root of the addition of their squares.

Therefore it can be calculated as;

$\sqrt{ {x}^(2) + {y}^(2) + z {}^(2) }$

Therefore ;

x = 63.5

y = 101

z = 57

The magnitude sum of the vectors is therefore;

$\sqrt{101 {}^(2) + 63.5 {}^(2) + 57 {}^(2) } \\ = √(17482.25) \\ = 132.2$

Therefore the sum of the vectors is 132.2