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If AB+AB+AB=B2 ,where A and B are different digits, then one of the solution is


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The equation you've provided is AB + AB + AB = B^2. To find a solution where A and B are different digits, let's consider one possibility:

Let A = 1 and B = 2.

Now, substitute these values into the equation:

12 + 12 + 12 = 2^2
36 = 4

The equation is not satisfied in this case because 36 does not equal 4.

It appears that there might be an issue with the equation or there are no integer solutions for A and B that make it valid. Please double-check the equation or provide more context if needed.
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User Gary Ye
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