Question

I need help on this asap! I should be able to solve this, but it's just difficult for some reason, I can't figure it out.

Answer 1

`\cfrac{ab+2c}{-bc}\qquad \begin{cases} a=-2\\ b=3\\ c=-6 \end{cases}\implies \cfrac{(-2)(3)~~ + ~~2(-6)}{-(3)(-6)} \\\\\\ \cfrac{-6~~ + ~~(-12)}{-(-18)}\implies \cfrac{-6-12}{18}\implies \cfrac{-18}{18}\implies \text{\LARGE -1}`