Answer:


Explanation:
To simplify √(40) to its lowest radical form, rewrite 40 as the product of 4 and 10:

Now, factor the number 4 into its prime factors:





Therefore,
is equivalent to
.

The radical rule states that:
![\sqrt[n]{a^m}=a^{(m)/(n)},\quad \textsf{assuming} \;a\geq 0](https://img.qammunity.org/2024/formulas/mathematics/high-school/jmb9kie48800e91zygx53sapmzfvks2fep.png)
Since a = a¹, and
, then the square root of a number can be written as:
![√(a)=\sqrt[2]{a^1}=a^{(1)/(2)}](https://img.qammunity.org/2024/formulas/mathematics/high-school/xkhfrl94puhul5olb75kvz0hi810hskapz.png)
So, in the context of the square root of 40:
![√(40)=\sqrt[2]{40^1}=40^{(1)/(2)](https://img.qammunity.org/2024/formulas/mathematics/high-school/riwied9a7txcsxndia5soza1w7m1y1lpp8.png)
Therefore,
is equivalent to
.