Answer:
The softball team can bring 15 players to the tournament.
Explanation:
We can model the situation using a linear equation in slope-intercept form, whose general equation is given by:
y = mx + b, where
- (x, y) is any point on the line,
- m is the slope (change in y / change in x),
- and b is the y-intercept (y value when x = 0)
Identifying the slope:
Since it costs $53 per player, this is the slope as cost (y) changes per each player needing a meal (x).
Identifying the y-intercept and equation representing the situation:
We know that the team pays $1148.50 for the bus and additional costs come from the number of players needing meals.
Thus, 1148.50 is the y-intercept.
Therefore, the equation modeling the situation is y = 53x + 1148.50
Solving for x:
Since the team raised $1943.50 for the tournament, we can substitute 1943.50 for y in our equation to solve for x, the number of players the team can bring to the tournament:
(1943.50 = 53x + 1148.50) - 1148.50
(795 = 53x) / 53
15 = x
Thus, the team can take no more than 15 players to the tournament, in order to not exceed their budget.