Answer:
Let's break down the problem step by step:
1. By what factor does organism A's population grow in the first five days?
Organism A's population doubles every day for 5 days. So, the factor by which it grows can be expressed as 2^5 since it doubles 5 times. This simplifies to 32.
2. Write (2–1)^3 with the same base but one exponent.
(2–1)^3 is equivalent to 1^3, which is simply 1.
3. By combining the increase and decrease, find an exponential expression for the total change in organism A's population after 8 days.
In the first 5 days, the population grows by a factor of 32, and then it decreases by a factor of (1/2)^3 during the next 3 days. So, the total change in organism A's population after 8 days can be expressed as 32 * (1/2)^3.
4. Write an exponential expression showing organism B's increase in population over the same 8 days.
Organism B's population also doubles every day for 8 days. So, the factor by which it grows can be expressed as 2^8, which is 256.
5. Use your answers to questions 3 and 4 to write an expression for how many times greater organism B's population is than organism A's population after 8 days.
To find how many times greater organism B's population is than organism A's population, divide the growth factor of B by the total change factor of A:
Organism B's population / Organism A's population = 256 / (32 * (1/2)^3)
Now, simplify this expression step by step:
Organism B's population / Organism A's population = 256 / (32 * (1/8))
Next, simplify the denominator:
Organism B's population / Organism A's population = 256 / (4)
Finally, divide to get the answer:
Organism B's population / Organism A's population = 64
So, organism B's population is 64 times greater than organism A's population after 8 days.
Explanation: