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The rectangle is given A=6x^2y+4y^2x and the width of rectangle is w=2xy what is the perimeter of the rectangle ?​

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User Jubal
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1 Answer

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Final answer:

The perimeter of the rectangle is 12x^2y + 8y^2x + 4xy.

Step-by-step explanation:

To find the perimeter of a rectangle, we need to know its length and width. In this case, the length of the rectangle is given by the expression A = 6x^2y + 4y^2x, and the width is given as w = 2xy. The perimeter can be calculated by adding the lengths of all four sides of the rectangle.

The length of the rectangle is A, and the width is w. So, the perimeter, P, is given by the equation P = 2A + 2w. Substituting the given values, we have:

P = 2(6x^2y + 4y^2x) + 2(2xy) = 12x^2y + 8y^2x + 4xy

Therefore, the perimeter of the rectangle is 12x^2y + 8y^2x + 4xy.

Learn more about Rectangle perimeter

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User Mario Carneiro
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