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The side of a square exceeds the side of the another square by 3 cm and the sum of the areas of the two squares is 225 sq. cm. Find the dimensions of the square.

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User Homm
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1 Answer

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Final answer:

The dimensions of the square are 12 cm by 12 cm.

Step-by-step explanation:

Let's call the side of the first square x cm and the side of the second square (x - 3) cm. The formula for the area of a square is A = s^2, where s is the length of a side. The sum of the areas of the two squares is given as 225 sq. cm, so we can write the equation:



x^2 + (x - 3)^2 = 225



Simplifying the equation, we get:



2x^2 - 6x + 9 = 225



2x^2 - 6x - 216 = 0



Factoring the equation, we have:



(2x + 18)(x - 12) = 0



Solving for x, we find that x = 12. Therefore, the dimensions of the square are 12 cm by 12 cm.

Learn more about Dimensions of a square

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User Canilho
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