Question

Solve 2-3z>=7(8-2z)+12

Answer 1

z ≥ 6

Explanation:

Step 1: Distribute the 7 and combine like terms on the right-hand side:

2 - 3z ≥ 7(8 - 2z) + 12

2 - 3z ≥ 56 - 14z + 12

2 - 3z ≥ 68 - 14z

Step 2: Subtract 2 from both sides:

(2 - 3z ≥ 68 - 14z) - 2

-3z ≥ 66 - 14z

Step 4: Add 14z to both sides:

(-3z ≥ 66 - 14z) + 14z

11z ≥ 66

Step 5: Divide both sides by 11 to solve for z:

(11z ≥ 66) / 11

z ≥ 6