asked 11.8k views
5 votes
A room measures 4m by 7m, where each measurement is made to the nearest meter. Find the upper and lower bounds for the area of the room.

asked
User Ayrnieu
by
8.1k points

1 Answer

1 vote

Final answer:

The upper bound for the area of the room is 33.75 square meters, while the lower bound is 22.75 square meters.

Step-by-step explanation:

The upper and lower bounds for the area of the room can be found by considering the maximum and minimum possible measurements for each side length. In this case, the maximum length would be 4.5m (4m rounded up) and the minimum length would be 3.5m (4m rounded down). Similarly, the maximum width would be 7.5m (7m rounded up) and the minimum width would be 6.5m (7m rounded down).

To find the upper bound for the area, we can use the maximum length and maximum width: 4.5m × 7.5m = 33.75 square meters. To find the lower bound for the area, we can use the minimum length and minimum width: 3.5m × 6.5m = 22.75 square meters.

Learn more about Area of a rectangle

answered
User RAHUL KUNDU
by
8.0k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.