Question

4. Algebraically determine the solution to the equation 64(x−5)=16(3x). [2 Marks]

Answer 1

Hello!

Answer:

`\Large \boxed{\sf x = 20}`

Explanation:

→ We want to solve this equation:

`\sf 64(x-5)=16(3x)`

◼ Simplify both sides:

`\sf 64x-320=48x`

◼ Subtract 64x from both sides:

`\sf 64x-320-64x=48x-64x`

◼ Simplify both sides:

`\sf -320=-16x`

◼ Divide both sides by -16:

`\sf (-320)/(-16) = (-16x)/(-16)`

◼ Simplify both sides:

`\boxed{\sf x = 20}`

Conclusion:

The solution of the equation 64(x-5) = 16(3x) is 20.