Final answer:
The problem appears to be about a rectangle with unknown length and width. Given that the width is 5 meters shorter than the length and that the perimeter is 38 meters, you can use these conditions to set up two equations, solve them simultaneously to find that the length is 11 meters and the width is 6 meters.
Step-by-step explanation:
The question seems to be about a rectangular shape where the width is 5 meters less than its length, and the perimeter is 38 meters. The formula for the perimeter of a rectangle is 2*(length+width).
First, we set up two equations using the given information. If we let L represent the length, and W represent the width, we can state this as: W = L - 5 (since the width is 5 meters less than the length) and 2*(L + W) = 38 (the second equation representing the perimeter).
Substituting W in the second equation gives us: 2*(L + (L-5)) = 38, which simplifies to 2*(2L - 5) = 38. Solving this gives L = 11 meters, and substituting L=11 into the first equation gives W = 6 meters.
Learn more about Rectangle Perimeter