Question

Find the dimensions of the rectangle meeting the specified conditions.

width
length
The perimeter is 70 meters and the length is 5 meters greater than the width.
m
m

Answer 1

`w=(35)/(6) =5.83333333`

`l=(175)/(6) =29.1666667`

Explanation:

`p=2l+2w`

`p=70`

`70=2l+2w`

`l=5w`

replace
`l` with
`w` in the perimeter equation

`70=2(5w)+2w`

simplify

`70=10w+2w\\70=12w`

divide both sides by 12

`(70)/(12) =w`

simplify fraction

`(35)/(6)=w`

replace
`w` with
`(35)/(6)` in perimeter equation

`70=2l+2((35)/(6) )`

simplify

`70=2l+(35)/(3)`

subtract both sides by
`(35)/(3)`

`70-(35)/(3)=2l`

change 70 into fraction by multiplying numerator (70) and denominator (1) by 3

`(210)/(3)-(35)/(3)=2l`

simplify

`(175)/(3)=2l`

divide both sides by 2

`(175)/(6) =l`