Question

The round-trip distance between City A and City B is 150 miles. City C and City D are between City A and City B. You make the round trip in 3 days. On the first day, you leave City A and travel 46.8 miles and stay in City C. On the second day, you travel 51.4 miles and stay in City D. Find the distance between City B and City D, in miles.

Answer 1

23.2 miles

Explanation:

Since a round trip from City A and City B is 150 miles, we already know that the distance between the two cities is 75 miles.

When you travel 46.8 miles towards City B and stay in City C, you are 28.2 miles away from City B because 75 - 46.8 = 28.2

Since the miles to get to the city are less than what is stated in the question (46.8), we're gonna simplify.

46.8 - 28.2 = 23.2

The 28.2 miles are the miles remaining to get to City B. This shows that the 46.8 miles were spent driving towards City B and driving away from City B. The 23.2 miles were spent driving away, towards City D. This shows that City D is 23.2 miles away from City B.