Question

10.

A snail travels at a rate of 2.37 feet per minute.
a. Write a rule to describe the function.
b. How far will the snail travel in 6 minutes

A. d(t) = t/2.37; 2.53ft

B. d(t) = t + 2.37; 8.37 ft


C. d(t) = 2.37t; 14.22 ft


D. d(t) = 6t; 14.22 ft

Answer 1

D. d(t) = 6t; 14.22 ft

Explanation:

d(t)= 2.37t; 14.22 ft

d(t)= 2.37t; 14.22 ft

Answer:

a. f(t)=2.37t

b. 14.22 feet

Step-by-step explanation:

We are given that:

A snail travels at a rate of 2.37 feet per minute.

a. write a rule to describe a function.

Let t describe the time and f(t) be a function how far snail travels

then, f(t)=2.37×t

where the unit of t is in minutes and that of f(t) is feet

b. how far will the snail travel in 6 minutes

we have to find f(t) at t=6

f(6)= 2.37×6

= 14.22 feet

Hence, snail traveled 14.22 feet in 6 minutes

2.37/minute

14.22 feet in six minutes

Answer:

Rule for Distance is f(t) = 2.37t and distance covered in 6 minutes is 14.22 feet.

Step-by-step explanation:

Speed of Snail = 2.37 feet per minute

To write the rule we use relation of Speed, Distance and time

Distance = Speed × Time

So, Distance cover by snail in t minutes is given by f(t) = 2.37 × t

⇒ f(t) = 2.37t

Distance traveled by Snail in 6 minutes , f(6) = 2.37 × 6 = 14.22 feet

Therefore, Rule for Distance is f(t) = 2.37t and distance covered in 6 minutes is 14.22 feet.

Answer 2

C. d(t) = 2.37t; 14.22 ft

Explanation:

2.37 per minute is multiplication so A and B are definitely wrong

Another way to check is 2.37*6=14.22 so the answer is C