Question

Between 10 P.M. and 7:36 A.M.​, the water level in a swimming pool decreased by 8/15 . Assuming that the water level decreased at a constant​ rate, how much did the water level drop each​ hour?

Answer 1

The water level dropped approximately 0.056 (or \( \frac{1}{18} \)) of the pool's total water level per hour.

Explanation:

The time difference between 10 P.M. and 7:36 A.M. is 9 hours and 36 minutes, which is equivalent to 9.6 hours.

The water level in the swimming pool decreased by \( \frac{8}{15} \) during this time. To find out how much the water level dropped each hour, we can divide
`\( (8)/(15) \)` by 9.6 hours.

`\[\text{Rate of water level drop per hour} = ((8)/(15))/(9.6) \approx 0.056\]`

So, the water level dropped approximately 0.056 (or
`\( (1)/(18) \)`) of the pool's total water level per hour.